What is the derivative of 5sec^2(x) ?

The derivative of 5sec^2(x) is 10sec^2(x)tan(x)

What is the first derivative of 5sec^2(x) ?

The first derivative of 5sec^2(x) is 10sec^2(x)tan(x)

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derivative of

5 sec^{2} (x)

10 sec^{2} (x) tan (x)

Solution steps

\frac{d}{d x} (5 sec^{2} (x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 5 \frac{d}{d x} (sec^{2} (x))

Apply the chain rule:

2 sec (x) \frac{d}{d x} (sec (x))

= 2 sec (x) \frac{d}{d x} (sec (x))

\frac{d}{d x} (sec (x)) = sec (x) tan (x)

= 5 \cdot 2 sec (x) sec (x) tan (x)

Simplify

5 \cdot 2 sec (x) sec (x) tan (x) : 10 sec^{2} (x) tan (x)

= 10 sec^{2} (x) tan (x)

k = 1 \sum \infty \frac{x ^{k}}{k}

f (x) = sec (x) tan (x)

x^{2} - 2 x, 2 x - 3

\int_{0}^{1} \frac{93}{x ^{5}} d x

\int (x^{1.3} + 9 x^{3.5}) d x

What is the derivative of 5sec^2(x) ?
The derivative of 5sec^2(x) is 10sec^2(x)tan(x)
What is the first derivative of 5sec^2(x) ?
The first derivative of 5sec^2(x) is 10sec^2(x)tan(x)