What is the tangent of y= 1/(x^4),(-2, 1/16) ?

The tangent of y= 1/(x^4),(-2, 1/16) is y= 1/8 x+5/16

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tangent of y= 1/(x^4),(-2, 1/16)

tangent of

y = \frac{1}{x ^{4}}, (- 2, \frac{1}{16})

y = \frac{1}{8} x + \frac{5}{16}

Solution steps

Find the slope of

y = \frac{1}{x ^{4}} : \frac{d y}{d x} = - \frac{4}{x ^{5}}

Compute the slope of

y = \frac{1}{x ^{4}}

(- 2, \frac{1}{16}) : m = \frac{1}{8}

Find the line with slope m=

\frac{1}{8}

and passing through

(- 2, \frac{1}{16}) : y = \frac{1}{8} x + \frac{5}{16}

y = \frac{1}{8} x + \frac{5}{16}

\int (2 e^{x}) d x

x \to 0 - lim (\frac{x ^{2}}{6} - \frac{4}{x})

\int csc^{2} (3 x - 1) d x

\int_{0}^{1} \frac{24}{x ^{2} - 9} d x

\frac{1}{s ^{2} + 8}

What is the tangent of y= 1/(x^4),(-2, 1/16) ?
The tangent of y= 1/(x^4),(-2, 1/16) is y= 1/8 x+5/16