What is the derivative of f(x)=8x^2 ?

The derivative of f(x)=8x^2 is 16x

What is the first derivative of f(x)=8x^2 ?

The first derivative of f(x)=8x^2 is 16x

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derivative of

f (x) = 8 x^{2}

16 x

Solution steps

\frac{d}{d x} (8 x^{2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 8 \frac{d}{d x} (x^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 8 \cdot 2 x^{2 - 1}

Simplify

= 16 x

\frac{d}{d x} (ln (\frac{x ^{2} - 81}{k}))

\frac{\partial}{\partial x} (x^{3} + 3 x y^{2})

6 - 7 x

\frac{d}{d x} (sin^{12} (3 x^{4} - x))

\frac{d y}{d x} = \frac{( 2 + y ) ^{2}}{2 x - 1}

What is the derivative of f(x)=8x^2 ?
The derivative of f(x)=8x^2 is 16x
What is the first derivative of f(x)=8x^2 ?
The first derivative of f(x)=8x^2 is 16x