What is the solution for (x^2+xy-y^2)dx+xydy=0 ?

The solution for (x^2+xy-y^2)dx+xydy=0 is y=-\W(x/(c_{1)})x-x

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(x^2+xy-y^2)dx+xydy=0

(x^{2} + x y - y^{2}) d x + x y d y = 0

y = - W (\frac{x}{c _{1}}) x - x

Solution steps

(x^{2} + x y - y^{2}) d x + x y d y = 0

Solve using substitution:

y = - W (\frac{x}{c _{1}}) x - x

y = - W (\frac{x}{c _{1}}) x - x

x \to 0 lim ((x - 3) x)

sin^{5} (3 x^{2} - x + 13)

\frac{d}{d x} ((\frac{3}{4})^{x})

(5 x + 3) + (5 y - 5) y^{^{'}} = 0

\frac{d}{d x} ((x^{2} + 1)^{2})

What is the solution for (x^2+xy-y^2)dx+xydy=0 ?
The solution for (x^2+xy-y^2)dx+xydy=0 is y=-\W(x/(c_{1)})x-x