What is the tangent of y=2x+3cos(x) ?

The tangent of y=2x+3cos(x) is y=(2-3sin(a_{0}))x+3a_{0}sin(a_{0})+3cos(a_{0})

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tangent of y=2x+3cos(x)

tangent of

y = 2 x + 3 cos (x)

y = (2 - 3 sin (a_{0})) x + 3 a_{0} sin (a_{0}) + 3 cos (a_{0})

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, 2 a_{0} + 3 cos (a_{0}))

Find the slope of

y = 2 x + 3 cos (x) : \frac{d y}{d x} = 2 - 3 sin (x)

Compute the slope of

y = 2 x + 3 cos (x)

x = a_{0} : m = 2 - 3 sin (a_{0})

Find the line with slope m=

2 - 3 sin (a_{0})

and passing through

(a_{0}, 2 a_{0} + 3 cos (a_{0})) : y = (2 - 3 sin (a_{0})) x + 3 a_{0} sin (a_{0}) + 3 cos (a_{0})

y = (2 - 3 sin (a_{0})) x + 3 a_{0} sin (a_{0}) + 3 cos (a_{0})

x \to 0 lim (f (x))

\frac{\partial}{\partial x} ((4 + 5 y)^{x})

\int_{1}^{5} 5 r^{2} ln (r) d r

x \to \infty lim (c^{x})

x \to - \infty lim (2)

What is the tangent of y=2x+3cos(x) ?
The tangent of y=2x+3cos(x) is y=(2-3sin(a_{0}))x+3a_{0}sin(a_{0})+3cos(a_{0})