en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sum from n=9 to infinity of 1/(n(n-1))

Solution

n = 9 \sum \infty \frac{1}{n ( n - 1 )}

Solution

\frac{1}{8}

Solution steps

n = 9 \sum \infty \frac{1}{n ( n - 1 )}

Apply Telescoping Series Test:

\frac{1}{8}

= \frac{1}{8}

Popular Examples

derivative of x^2-2x derivative of

x^{2} - 2 x

integral of tan(x/4)

\int tan (\frac{x}{4}) d x

derivative of a/(1-bx)derivative of

\frac{a}{1 - b x}

(dy)/(dx)-5y=x^2

\frac{d y}{d x} - 5 y = x^{2}

taylor 7/x ,-1 taylor

\frac{7}{x}, - 1

Frequently Asked Questions (FAQ)

What is the sum from n=9 to infinity of 1/(n(n-1)) ?
The sum from n=9 to infinity of 1/(n(n-1)) is 1/8