What is the integral of 1/(t^{1/2)} ?

The integral of 1/(t^{1/2)} is 2t^{1/2}+C

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integral of 1/(t^{1/2)}

\int \frac{1}{t ^{\frac{1}{2}}} d t

2 t^{\frac{1}{2}} + C

Solution steps

\int \frac{1}{t ^{\frac{1}{2}}} d t

Apply the Power Rule

: 2 t^{\frac{1}{2}}

= 2 t^{\frac{1}{2}}

Add a constant to the solution

= 2 t^{\frac{1}{2}} + C

3 x + y^{2} = 13, x = 4 y

x = - y^{2} + 4, x = - 3 y

y^{3} d x + 2 (x^{3} - x y^{2}) d y = 0

\int \frac{2 x + 3}{( x + 7 ) ^{3}} d x

\frac{160 ( x + 1 )}{( x + 2 ) ^{2}}