What is the derivative of 2x+y ?

The derivative of 2x+y is 2+(dy)/(dx)

What is the first derivative of 2x+y ?

The first derivative of 2x+y is 2+(dy)/(dx)

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\frac{d}{d x} (2 x + y)

2 + \frac{d y}{d x}

Solution steps

\frac{d}{d x} (2 x + y)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x) + \frac{d y}{d x}

\frac{d}{d x} (2 x) = 2

= 2 + \frac{d y}{d x}

\frac{d}{d t} (t^{2} e^{- t})

x \cdot y^{2} \cdot y^{^{'}} = x^{3} + y^{3}

\int \frac{1}{1 + ( 2 x + 5 ) ^{2}} d x

11 x - 6 y x^{2} + 1 \frac{d y}{d x} = 0

\int t sec^{2} (5 t) d t

What is the derivative of 2x+y ?
The derivative of 2x+y is 2+(dy)/(dx)
What is the first derivative of 2x+y ?
The first derivative of 2x+y is 2+(dy)/(dx)