What is the sum from n=1 to infinity of (-0.3)^{n-1} ?

The sum from n=1 to infinity of (-0.3)^{n-1} is converges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sum from n=1 to infinity of (-0.3)^{n-1}

n = 1 \sum \infty (- 0.3)^{n - 1}

converges

Solution steps

n = 1 \sum \infty (- 0.3)^{n - 1}

Apply Series Ratio Test:

converges

= converges

x \to 3 + lim (\frac{5 x}{x ^{2} - 9})

\frac{d}{d x} (ln (cosh (2 x)))

\frac{d}{d x} (sin (x) + \frac{7}{4} cot (x))

2 y^{^{''}} + y^{^{'}} - 10 y = 0

\int 3 e^{- 0.8 x} d x

What is the sum from n=1 to infinity of (-0.3)^{n-1} ?
The sum from n=1 to infinity of (-0.3)^{n-1} is converges