What is the integral from pi/6 to pi of (sin(x)) ?

The integral from pi/6 to pi of (sin(x)) is 1+(sqrt(3))/2

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integral from pi/6 to pi of (sin(x))

\int_{\frac{π}{6}}^{π} (sin (x)) d x

1 + \frac{3}{2}

Decimal Notation

1.86602 \dots

Solution steps

\int_{\frac{π}{6}}^{π} sin (x) d x

Use the common integral:

\int sin (x) d x = - cos (x)

= [- cos (x)]_{\frac{π}{6}}^{π}

Compute the boundaries:

1 + \frac{3}{2}

= 1 + \frac{3}{2}

\frac{d}{d x} (\frac{x ^{2}}{ln ( x )} + 2 x)

\frac{d}{d x} (e^{- 12 x})

\int (1 - x - y)^{3} d y

(3, - 5), (5, - 5)

\int x^{2} ln^{2} (x) d x

What is the integral from pi/6 to pi of (sin(x)) ?
The integral from pi/6 to pi of (sin(x)) is 1+(sqrt(3))/2