What is the solution for y^'+3x^2y=xe^{-x^3} ?

The solution for y^'+3x^2y=xe^{-x^3} is y=(x^2)/(2e^{x^3)}+(c_{1})/(e^{x^3)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^'+3x^2y=xe^{-x^3}

y^{^{'}} + 3 x^{2} y = x e^{- x^{3}}

y = \frac{x ^{2}}{2 e ^{x^{3}}} + \frac{c _{1}}{e ^{x^{3}}}

Solution steps

y^{'} (x) + 3 x^{2} y = x e^{- x^{3}}

Solve linear ODE:

y = \frac{x ^{2}}{2 e ^{x^{3}}} + \frac{c _{1}}{e ^{x^{3}}}

y = \frac{x ^{2}}{2 e ^{x^{3}}} + \frac{c _{1}}{e ^{x^{3}}}

y^{^{'}} = \frac{3 sec ( y )}{( x + 5 ) ^{2}}

f (x) = 2^{30}

\frac{d}{d x} (lo g_{e} (\frac{4 x ^{2} - 9}{2 x - 3}))

\int_{- \infty}^{\infty} x^{23} e^{- x^{24}} d x

\frac{\partial}{\partial y} (\frac{2}{y ^{2} - x})

What is the solution for y^'+3x^2y=xe^{-x^3} ?
The solution for y^'+3x^2y=xe^{-x^3} is y=(x^2)/(2e^{x^3)}+(c_{1})/(e^{x^3)}