What is area y= 1/x ,y= 1/(x^2),x=4 ?

The answer to area y= 1/x ,y= 1/(x^2),x=4 is 2ln(2)-3/4

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area y= 1/x ,y= 1/(x^2),x=4

area

y = \frac{1}{x}, y = \frac{1}{x ^{2}}, x = 4

2 ln (2) - \frac{3}{4}

Decimal

0.63629 \dots

Solution steps

Apply the area formula:

\int_{1}^{4} \frac{1}{x} - \frac{1}{x ^{2}} d x

Solve

\int_{1}^{4} \frac{1}{x} - \frac{1}{x ^{2}} d x : 2 ln (2) - \frac{3}{4}

The area is:

= 2 ln (2) - \frac{3}{4}

x (x^{2} - 10 x + 30), x^{2}, 0, 5

\frac{d}{d x} (\frac{- sin ( x )}{cos ( x )})

f (x) = 4 x^{3} - 14 x^{2} + 49 x + 6

\int 6 x ln (x + 1) d x

\frac{d}{d x} (24 x)

What is area y= 1/x ,y= 1/(x^2),x=4 ?
The answer to area y= 1/x ,y= 1/(x^2),x=4 is 2ln(2)-3/4