What is the integral of (144)/(x^3-12x^2) ?

The integral of (144)/(x^3-12x^2) is -ln|x|+(12)/x+ln|x-12|+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (144)/(x^3-12x^2)

\int \frac{144}{x ^{3} - 12 x ^{2}} d x

- ln ∣ x ∣ + \frac{12}{x} + ln ∣ x - 12 ∣ + C

Solution steps

\int \frac{144}{x ^{3} - 12 x ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 144 \cdot \int \frac{1}{x ^{3} - 12 x ^{2}} d x

Take the partial fraction of

\frac{1}{x ^{3} - 12 x ^{2}} : - \frac{1}{144 x} - \frac{1}{12 x ^{2}} + \frac{1}{144 ( x - 12 )}

= 144 \cdot \int - \frac{1}{144 x} - \frac{1}{12 x ^{2}} + \frac{1}{144 ( x - 12 )} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= 144 (- \int \frac{1}{144 x} d x - \int \frac{1}{12 x ^{2}} d x + \int \frac{1}{144 ( x - 12 )} d x)

\int \frac{1}{144 x} d x = \frac{1}{144} ln ∣ x ∣

\int \frac{1}{12 x ^{2}} d x = - \frac{1}{12 x}

\int \frac{1}{144 ( x - 12 )} d x = \frac{1}{144} ln ∣ x - 12 ∣

= 144 (- \frac{1}{144} ln ∣ x ∣ - (- \frac{1}{12 x}) + \frac{1}{144} ln ∣ x - 12 ∣)

Simplify

144 (- \frac{1}{144} ln ∣ x ∣ - (- \frac{1}{12 x}) + \frac{1}{144} ln ∣ x - 12 ∣) : - ln ∣ x ∣ + \frac{12}{x} + ln ∣ x - 12 ∣

= - ln ∣ x ∣ + \frac{12}{x} + ln ∣ x - 12 ∣

Add a constant to the solution

= - ln ∣ x ∣ + \frac{12}{x} + ln ∣ x - 12 ∣ + C

f (x) = 5 cos (x), at x = \frac{π}{3}

cos (x), - cos (x) + 2

f (2) = \frac{x + 11}{x - 9}

\frac{x ^{4}}{2} - \frac{3}{2} x^{2} - x

t \to 1 lim (\frac{t ^{2} - 4}{t - 2})

What is the integral of (144)/(x^3-12x^2) ?
The integral of (144)/(x^3-12x^2) is -ln|x|+(12)/x+ln|x-12|+C