What is the derivative of 2x^4-8x+3 ?

The derivative of 2x^4-8x+3 is 8x^3-8

What is the first derivative of 2x^4-8x+3 ?

The first derivative of 2x^4-8x+3 is 8x^3-8

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\frac{d}{d x} (2 x^{4} - 8 x + 3)

8 x^{3} - 8

Solution steps

\frac{d}{d x} (2 x^{4} - 8 x + 3)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{4}) - \frac{d}{d x} (8 x) + \frac{d}{d x} (3)

\frac{d}{d x} (2 x^{4}) = 8 x^{3}

\frac{d}{d x} (8 x) = 8

\frac{d}{d x} (3) = 0

= 8 x^{3} - 8 + 0

Simplify

= 8 x^{3} - 8

\frac{d}{d x} ((x^{2})^{- 1})

\frac{\partial}{\partial x} (\frac{y}{1 + x ^{2} + y ^{2}})

\frac{s}{( s ^{2} + 1 ) ( s ^{2} + 4 )}

x \to 1 lim (2 x^{3} - 5 x^{2} + x + 9)

\int \frac{3 x ^{2} + 2 x - 10}{x ^{3} + x ^{2} - 10 x + 8} d x

What is the derivative of 2x^4-8x+3 ?
The derivative of 2x^4-8x+3 is 8x^3-8
What is the first derivative of 2x^4-8x+3 ?
The first derivative of 2x^4-8x+3 is 8x^3-8