What is the tangent of f(x)=2x^2+x-1,\at a=-2 ?

The tangent of f(x)=2x^2+x-1,\at a=-2 is y=(4a+1)x-2a^2-1

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tangent of f(x)=2x^2+x-1,\at a=-2

tangent of

f (x) = 2 x^{2} + x - 1, at a = - 2

y = (4 a + 1) x - 2 a^{2} - 1

Solution steps

Compute the tangent line to the general point

x = a

Find the tangent point:

(a, 2 a^{2} + a - 1)

Find the slope of

f (x) = 2 x^{2} + x - 1 : \frac{df ( x )}{d x} = 4 x + 1

Compute the slope of

f (x) = 2 x^{2} + x - 1

x = a : m = 4 a + 1

Find the line with slope m=

4 a + 1

and passing through

(a, 2 a^{2} + a - 1) : y = (4 a + 1) x - 2 a^{2} - 1

y = (4 a + 1) x - 2 a^{2} - 1

\int e^{x} x cos (x) d x

f (x) = 1 - 2 x

x \to 6 lim (x^{3} + 4 x)

\frac{d}{d x} (ln (x^{7} sin^{2} (x)))

\int \frac{1}{x ^{2} x ^{2} + a ^{2}} d x

What is the tangent of f(x)=2x^2+x-1,\at a=-2 ?
The tangent of f(x)=2x^2+x-1,\at a=-2 is y=(4a+1)x-2a^2-1