What is the derivative of x^3+2x^2+x ?

The derivative of x^3+2x^2+x is 3x^2+4x+1

What is the first derivative of x^3+2x^2+x ?

The first derivative of x^3+2x^2+x is 3x^2+4x+1

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\frac{d}{d x} (x^{3} + 2 x^{2} + x)

3 x^{2} + 4 x + 1

Solution steps

\frac{d}{d x} (x^{3} + 2 x^{2} + x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) + \frac{d}{d x} (2 x^{2}) + \frac{d x}{d x}

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d x}{d x} = 1

= 3 x^{2} + 4 x + 1

cos^{2} (z)

\int 7 x^{5} e^{- x^{3}} d x

\int x (y) d x

\frac{d}{d x} (x^{4} ln (x) - \frac{1}{3} x^{3})

x^{2} - x, x

What is the derivative of x^3+2x^2+x ?
The derivative of x^3+2x^2+x is 3x^2+4x+1
What is the first derivative of x^3+2x^2+x ?
The first derivative of x^3+2x^2+x is 3x^2+4x+1