What is the integral of sin(x)e^x ?

The integral of sin(x)e^x is -(e^xcos(x))/2+(e^xsin(x))/2+C

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integral of sin(x)e^x

\int sin (x) e^{x} d x

- \frac{e ^{x} cos ( x )}{2} + \frac{e ^{x} sin ( x )}{2} + C

Solution steps

\int sin (x) e^{x} d x

Apply Integration By Parts

: - e^{x} cos (x) - \int - e^{x} cos (x) d x

= - e^{x} cos (x) - \int - e^{x} cos (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - e^{x} cos (x) - (- \int e^{x} cos (x) d x)

Apply Integration By Parts

: e^{x} sin (x) - \int e^{x} sin (x) d x

= - e^{x} cos (x) - (- (e^{x} sin (x) - \int e^{x} sin (x) d x))

Therefore

\int e^{x} sin (x) d x = - e^{x} cos (x) - (- (e^{x} sin (x) - \int e^{x} sin (x) d x))

Isolate

\int e^{x} sin (x) d x

= - \frac{e ^{x} cos ( x )}{2} + \frac{e ^{x} sin ( x )}{2}

Add a constant to the solution

= - \frac{e ^{x} cos ( x )}{2} + \frac{e ^{x} sin ( x )}{2} + C

e^{5 t}

\int (x^{3} + 2)^{\frac{1}{2}} \cdot x^{2} d x

\frac{d}{d x} (sec^{2} (5 x^{2}))

\frac{\partial}{\partial x} (2 x^{2} y - y^{3} + x)

What is the integral of sin(x)e^x ?
The integral of sin(x)e^x is -(e^xcos(x))/2+(e^xsin(x))/2+C