What is the solution for (dy}{dx}=(\frac{(xy)^2)/8+y^2) ?

The solution for (dy}{dx}=(\frac{(xy)^2)/8+y^2) is y=-(24)/(x^3+24x+c_{1)}

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(dy}{dx}=(\frac{(xy)^2)/8+y^2)

\frac{d y}{d x} = (\frac{( x y ) ^{2}}{8} + y^{2})

y = - \frac{24}{x ^{3} + 24 x + c _{1}}

Solution steps

\frac{d y}{d x} = (\frac{( x y ) ^{2}}{8} + y^{2})

Solve separable ODE:

y = - \frac{24}{x ^{3} + 24 x + c _{1}}

y = - \frac{24}{x ^{3} + 24 x + c _{1}}

\frac{d ^{2}}{d x ^{2}} (ln (x))

y^{^{''}} + 4.5 y^{^{'}} = 0

\int x + 4 - \frac{4}{x} d x

\frac{2 t + t}{t + 3}

\frac{d}{d x} (x sin (x) tan (x))

What is the solution for (dy}{dx}=(\frac{(xy)^2)/8+y^2) ?
The solution for (dy}{dx}=(\frac{(xy)^2)/8+y^2) is y=-(24)/(x^3+24x+c_{1)}