What is the integral from 0 to infinity of 3e^{-3x} ?

The integral from 0 to infinity of 3e^{-3x} is 1

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integral from 0 to infinity of 3e^{-3x}

\int_{0}^{\infty} 3 e^{- 3 x} d x

1

Solution steps

\int_{0}^{\infty} 3 e^{- 3 x} d x

Compute the indefinite integral:

\int 3 e^{- 3 x} d x = - e^{- 3 x} + C

Compute the boundaries:

\int_{0}^{\infty} 3 e^{- 3 x} d x = 0 - (- 1)

= 0 - (- 1)

Simplify

= 1

\int_{0}^{1} \frac{1}{( x - 1 ) ^{\frac{2}{3}}} d x

\frac{d}{d x} ((8 x)^{\frac{1}{3}})

\int - cos (t) sin^{2} (t) d t

\frac{d}{d x} (\frac{e ^{x}}{e ^{x} + 5})

What is the integral from 0 to infinity of 3e^{-3x} ?
The integral from 0 to infinity of 3e^{-3x} is 1