en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{''}+4x=0

Solution

x^{^{''}} + 4 x = 0

Solution

x = c_{1} cos (2 t) + c_{2} sin (2 t)

Solution steps

x^{''} (t) + 4 x = 0

Solve linear ODE:

x = c_{1} cos (2 t) + c_{2} sin (2 t)

x = c_{1} cos (2 t) + c_{2} sin (2 t)

Popular Examples

sum from n=1 to infinity of 1/(n+1^{-n)}

n = 1 \sum \infty \frac{1}{n + 1 ^{- n}}

5y^{''}+15y^'-20y=0

5 y^{^{''}} + 15 y^{^{'}} - 20 y = 0

integral of (x^2-x+1)

\int (x^{2} - x + 1) d x

integral of 6/(x^2sqrt(x^2+16))

\int \frac{6}{x ^{2} x ^{2} + 16} d x

limit as x approaches 2 of x+1

x \to 2 lim (x + 1)

Frequently Asked Questions (FAQ)

What is the solution for x^{''}+4x=0 ?
The solution for x^{''}+4x=0 is x=c_{1}cos(2t)+c_{2}sin(2t)