What is the integral from 0 to infinity of sin(2x) ?

The integral from 0 to infinity of sin(2x) is diverges

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integral from 0 to infinity of sin(2x)

\int_{0}^{\infty} sin (2 x) d x

diverges

Solution steps

\int_{0}^{\infty} sin (2 x) d x

Compute the indefinite integral:

\int sin (2 x) d x = - \frac{1}{2} cos (2 x) + C

Compute the boundaries:

\int_{0}^{\infty} sin (2 x) d x =

diverges

= diverges

x \to 2 lim (\frac{3 x + 1}{x + 2})

\frac{d}{d t} (0.00225 t e^{- 0.0467 t})

\frac{\partial}{\partial x} (x y (sin ((x^{5}) + y^{5})))

\int_{- 1}^{2} \frac{1}{x ^{2}} d x

\frac{d}{d x} (∣ x - 2 ∣)

What is the integral from 0 to infinity of sin(2x) ?
The integral from 0 to infinity of sin(2x) is diverges