What is the limit as x approaches 3 of sqrt(8x^2+9) ?

The limit as x approaches 3 of sqrt(8x^2+9) is 9

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limit as x approaches 3 of sqrt(8x^2+9)

x \to 3 lim (8 x^{2} + 9)

9

Solution steps

x \to 3 lim (8 x^{2} + 9)

Plug in the value

x = 3

= 8 \cdot 3^{2} + 9

Simplify

8 \cdot 3^{2} + 9 : 9

= 9

\frac{x - 3}{x - 3}

x^{3}, 3 x - 2

y = \frac{27}{x ^{2} + 9}, (- 3, \frac{3}{2})

x \to \infty + lim (3 x^{2} - 8)

What is the limit as x approaches 3 of sqrt(8x^2+9) ?
The limit as x approaches 3 of sqrt(8x^2+9) is 9