What is the solution for (dy)/(dx)+4xy^3=0 ?

The solution for (dy)/(dx)+4xy^3=0 is y=sqrt(-1/(2(-2x^2+c_{1)))},y=-sqrt(-1/(2(-2x^2+c_{1)))}

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(dy)/(dx)+4xy^3=0

\frac{d y}{d x} + 4 x y^{3} = 0

y = - \frac{1}{2 ( - 2 x ^{2} + c _{1} )}, y = - - \frac{1}{2 ( - 2 x ^{2} + c _{1} )}

Solution steps

\frac{d y}{d x} + 4 x y^{3} = 0

Solve separable ODE:

y = - \frac{1}{2 ( - 2 x ^{2} + c _{1} )}, y = - - \frac{1}{2 ( - 2 x ^{2} + c _{1} )}

y = - \frac{1}{2 ( - 2 x ^{2} + c _{1} )}, y = - - \frac{1}{2 ( - 2 x ^{2} + c _{1} )}

f (x) = (- 16 x^{2} + 36)^{2}

\frac{d}{d x} (arctan (tanh (x)))

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\int \frac{1}{2 x ^{2} - 4 x + 6} d x

\int_{0}^{1} 2 π x (33 - 33 x) d x

What is the solution for (dy)/(dx)+4xy^3=0 ?
The solution for (dy)/(dx)+4xy^3=0 is y=sqrt(-1/(2(-2x^2+c_{1)))},y=-sqrt(-1/(2(-2x^2+c_{1)))}