What is the solution for (dy)/(dx)= y/(y-x) ?

The solution for (dy)/(dx)= y/(y-x) is y=x+sqrt(x^2+c_{1)},y=x-sqrt(x^2+c_{1)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dy)/(dx)= y/(y-x)

\frac{d y}{d x} = \frac{y}{y - x}

y = x + x^{2} + c_{1}, y = x - x^{2} + c_{1}

Solution steps

\frac{d y}{d x} = \frac{y}{y - x}

Solve exact ODE:

y = x + x^{2} + c_{1}, y = x - x^{2} + c_{1}

y = x + x^{2} + c_{1}, y = x - x^{2} + c_{1}

\frac{\partial}{\partial x} (2 (x e^{\frac{x}{2} + y} + 1))

\frac{d}{d x} (2 e^{x} + 3 x - ln (x))

\int - \frac{1}{2} sin (2 x) d x

x \to 80 lim (82 - x)

\int 2 sin (π x) d x

What is the solution for (dy)/(dx)= y/(y-x) ?
The solution for (dy)/(dx)= y/(y-x) is y=x+sqrt(x^2+c_{1)},y=x-sqrt(x^2+c_{1)}