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Popular >

y^'-y=2xe^{2x}

Solution

y^{^{'}} - y = 2 x e^{2 x}

Solution

y = 2 e^{2 x} (x - 1) + c_{1} e^{x}

Solution steps

y^{'} (x) - y = 2 x e^{2 x}

Solve linear ODE:

y = 2 e^{2 x} (x - 1) + c_{1} e^{x}

y = 2 e^{2 x} (x - 1) + c_{1} e^{x}

Popular Examples

f^'(x)=sqrt(x)(6+5x)

f^{^{'}} (x) = x (6 + 5 x)

tangent of f(x)= 1/(sqrt(10x)),\at x=9 tangent of

f (x) = \frac{1}{10 x}, at x = 9

integral of x^6+1/(sqrt(1-4x^2))

\int x^{6} + \frac{1}{1 - 4 x ^{2}} d x

laplacetransform e^{-4t}laplace transform

e^{- 4 t}

(i)^{^{'}}

Frequently Asked Questions (FAQ)

What is the solution for y^'-y=2xe^{2x} ?
The solution for y^'-y=2xe^{2x} is y=2e^{2x}(x-1)+c_{1}e^x