What is the derivative of y=(x^2+3x)^2 ?

The derivative of y=(x^2+3x)^2 is 2(x^2+3x)(2x+3)

What is the first derivative of y=(x^2+3x)^2 ?

The first derivative of y=(x^2+3x)^2 is 2(x^2+3x)(2x+3)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

y = (x^{2} + 3 x)^{2}

2 (x^{2} + 3 x) (2 x + 3)

Solution steps

\frac{d}{d x} ((x^{2} + 3 x)^{2})

Apply the chain rule:

2 (x^{2} + 3 x) \frac{d}{d x} (x^{2} + 3 x)

= 2 (x^{2} + 3 x) \frac{d}{d x} (x^{2} + 3 x)

\frac{d}{d x} (x^{2} + 3 x) = 2 x + 3

= 2 (x^{2} + 3 x) (2 x + 3)

\frac{d}{d x} (coth (x))

x \to 0 + lim (e^{\frac{1}{x}} \cdot x)

x \to 1 lim (\frac{x ^{4} - 1}{x + 1})

x \to 4 lim (5 x + 6)

n \to \infty lim (\frac{n}{3})

What is the derivative of y=(x^2+3x)^2 ?
The derivative of y=(x^2+3x)^2 is 2(x^2+3x)(2x+3)
What is the first derivative of y=(x^2+3x)^2 ?
The first derivative of y=(x^2+3x)^2 is 2(x^2+3x)(2x+3)