What is the derivative of 2x^3-6x^2 ?

The derivative of 2x^3-6x^2 is 6x^2-12x

What is the first derivative of 2x^3-6x^2 ?

The first derivative of 2x^3-6x^2 is 6x^2-12x

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\frac{d}{d x} (2 x^{3} - 6 x^{2})

6 x^{2} - 12 x

Solution steps

\frac{d}{d x} (2 x^{3} - 6 x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{3}) - \frac{d}{d x} (6 x^{2})

\frac{d}{d x} (2 x^{3}) = 6 x^{2}

\frac{d}{d x} (6 x^{2}) = 12 x

= 6 x^{2} - 12 x

y^{^{'}} = y (1 - 0.0002 y)

\frac{1}{( s + 2 ) ( s ^{2} - 2 s + 5 )}

\int_{- 3}^{- 1} x^{2} e^{x^{3} + 27} d x

\int tan^{2} (a x) cos (a x) d x

\int e^{x} arctan (e^{x}) d x

What is the derivative of 2x^3-6x^2 ?
The derivative of 2x^3-6x^2 is 6x^2-12x
What is the first derivative of 2x^3-6x^2 ?
The first derivative of 2x^3-6x^2 is 6x^2-12x