What is the derivative of Q(x)=x^4+8x^2+16 ?

The derivative of Q(x)=x^4+8x^2+16 is 4x^3+16x

What is the first derivative of Q(x)=x^4+8x^2+16 ?

The first derivative of Q(x)=x^4+8x^2+16 is 4x^3+16x

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derivative of

Q (x) = x^{4} + 8 x^{2} + 16

4 x^{3} + 16 x

Solution steps

\frac{d}{d x} (x^{4} + 8 x^{2} + 16)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{4}) + \frac{d}{d x} (8 x^{2}) + \frac{d}{d x} (16)

\frac{d}{d x} (x^{4}) = 4 x^{3}

\frac{d}{d x} (8 x^{2}) = 16 x

\frac{d}{d x} (16) = 0

= 4 x^{3} + 16 x + 0

Simplify

= 4 x^{3} + 16 x

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What is the derivative of Q(x)=x^4+8x^2+16 ?
The derivative of Q(x)=x^4+8x^2+16 is 4x^3+16x
What is the first derivative of Q(x)=x^4+8x^2+16 ?
The first derivative of Q(x)=x^4+8x^2+16 is 4x^3+16x