What is the slope of 3x^3+5y^3=1 ?

The slope of 3x^3+5y^3=1 is -(3x^2)/(5^{1/3)(-3x^3+1)^{2/3}}

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slope of 3x^3+5y^3=1

slope

3 x^{3} + 5 y^{3} = 1

- \frac{3 x ^{2}}{5 ^{\frac{1}{3}} ( - 3 x ^{3} + 1 ) ^{\frac{2}{3}}}

Solution steps

3 x^{3} + 5 y^{3} = 1

Isolate

y

for

In order to find the slope of the function, take the derivative of

- \frac{3 x ^{2}}{5 ^{\frac{1}{3}} ( - 3 x ^{3} + 1 ) ^{\frac{2}{3}}}

y^{^{'}} - e^{7 x + y} = 0

\frac{d}{d x} (3 x^{3} + cos (x))

x \to 2 lim (3 x + a)

x^{2}, 25, 0, 5

\int x^{2} + 4 d x

What is the slope of 3x^3+5y^3=1 ?
The slope of 3x^3+5y^3=1 is -(3x^2)/(5^{1/3)(-3x^3+1)^{2/3}}