What is the derivative of 2sin(2x) ?

The derivative of 2sin(2x) is 4cos(2x)

What is the first derivative of 2sin(2x) ?

The first derivative of 2sin(2x) is 4cos(2x)

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derivative of

2 sin (2 x)

4 cos (2 x)

Solution steps

\frac{d}{d x} (2 sin (2 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (sin (2 x))

Apply the chain rule:

cos (2 x) \frac{d}{d x} (2 x)

= cos (2 x) \frac{d}{d x} (2 x)

\frac{d}{d x} (2 x) = 2

= 2 cos (2 x) \cdot 2

Simplify

= 4 cos (2 x)

f (x) = 3 x + 7

\int 2 x^{2} + 4 d x

y = x^{2} - 4 x, y = 3 x

f (x) = \frac{20000}{2 + 123 e ^{- 0.1 (x)}}

x \to 7 + lim (x)

What is the derivative of 2sin(2x) ?
The derivative of 2sin(2x) is 4cos(2x)
What is the first derivative of 2sin(2x) ?
The first derivative of 2sin(2x) is 4cos(2x)