What is the tangent of 6cos(t),\at t=-pi/4 ?

The tangent of 6cos(t),\at t=-pi/4 is y=3sqrt(2)t+3sqrt(2)+(3pi)/(2sqrt(2))

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tangent of 6cos(t),\at t=-pi/4

tangent of

6 cos (t), at t = - \frac{π}{4}

y = 32 t + 32 + \frac{3 π}{2 2}

Solution steps

Find the tangent point:

(- \frac{π}{4}, 32)

Find the slope of

y = 6 cos (t) : \frac{d y}{d t} = - 6 sin (t)

Compute the slope of

y = 6 cos (t)

t = - \frac{π}{4} : m = 32

Find the line with slope m=

32

and passing through

(- \frac{π}{4}, 32) : y = 32 t + 32 + \frac{3 π}{2 2}

y = 32 t + 32 + \frac{3 π}{2 2}

2 s + 1

f (x) = x^{4} - 4 x^{3} + 2 x^{2} - 6, at x = 1

\int \frac{x ^{2}}{x ^{2} + x + 12} d x

\int \frac{1}{- t ^{2} + 3 t - 2} d t

\int e^{\frac{x ^{2}}{4}} d x

What is the tangent of 6cos(t),\at t=-pi/4 ?
The tangent of 6cos(t),\at t=-pi/4 is y=3sqrt(2)t+3sqrt(2)+(3pi)/(2sqrt(2))