What is the derivative of 32cos(2x) ?

The derivative of 32cos(2x) is -64sin(2x)

What is the first derivative of 32cos(2x) ?

The first derivative of 32cos(2x) is -64sin(2x)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (32 cos (2 x))

- 64 sin (2 x)

Solution steps

\frac{d}{d x} (32 cos (2 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 32 \frac{d}{d x} (cos (2 x))

Apply the chain rule:

- sin (2 x) \frac{d}{d x} (2 x)

= - sin (2 x) \frac{d}{d x} (2 x)

\frac{d}{d x} (2 x) = 2

= 32 (- sin (2 x) \cdot 2)

Simplify

= - 64 sin (2 x)

x \to - 2 lim (3)

\frac{d}{d x} (8 sec^{2} (x))

\int_{1}^{2} x e^{x^{2}} d x

\int - 2 tan (2 y) d y

\frac{\partial}{\partial x} (9 - x^{2} + x y - 3 y^{2})

What is the derivative of 32cos(2x) ?
The derivative of 32cos(2x) is -64sin(2x)
What is the first derivative of 32cos(2x) ?
The first derivative of 32cos(2x) is -64sin(2x)