What is the derivative of x^2+8x-5 ?

The derivative of x^2+8x-5 is 2x+8

What is the first derivative of x^2+8x-5 ?

The first derivative of x^2+8x-5 is 2x+8

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\frac{d}{d x} (x^{2} + 8 x - 5)

2 x + 8

Solution steps

\frac{d}{d x} (x^{2} + 8 x - 5)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (8 x) - \frac{d}{d x} (5)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (8 x) = 8

\frac{d}{d x} (5) = 0

= 2 x + 8 - 0

Simplify

= 2 x + 8

x^{\frac{11}{12}}

y^{2} = x, y = - x + 2

e^{- 4 t} + 5

x^{\frac{1}{2}}, 1

\frac{d}{d x} (sin (x^{2}) + \frac{1 - x}{1 + x})

What is the derivative of x^2+8x-5 ?
The derivative of x^2+8x-5 is 2x+8
What is the first derivative of x^2+8x-5 ?
The first derivative of x^2+8x-5 is 2x+8