What is area y=6cos(pix),y=8x^2-2,-0.5,0.5 ?

The answer to area y=6cos(pix),y=8x^2-2,-0.5,0.5 is 5.15305…

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area y=6cos(pix),y=8x^2-2,-0.5,0.5

area

y = 6 cos (π x), y = 8 x^{2} - 2, - 0.5, 0.5

5.15305 \dots

Solution steps

Apply the area formula:

\int_{- 0.5}^{0.5} 6 cos (π x) - (8 x^{2} - 2) d x

Solve

\int_{- 0.5}^{0.5} 6 cos (π x) - (8 x^{2} - 2) d x : 5.15305 \dots

The area is:

= 5.15305 \dots

\int \frac{1}{2 + 2 x} d x

\int sin (ln (13 x)) d x

f (x) = 2 x^{2} + 5 x, at x = - 3

\frac{d ^{2} h}{d t ^{2}} = - kh

x \to 2 lim (2 x^{2} - 3 x + 1)

What is area y=6cos(pix),y=8x^2-2,-0.5,0.5 ?
The answer to area y=6cos(pix),y=8x^2-2,-0.5,0.5 is 5.15305…