What is the integral from 0 to pi/2 of sec(x) ?

The integral from 0 to pi/2 of sec(x) is diverges

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integral from 0 to pi/2 of sec(x)

\int_{0}^{\frac{π}{2}} sec (x) d x

diverges

Solution steps

\int_{0}^{\frac{π}{2}} sec (x) d x

Use the common integral:

\int sec (x) d x = ln ∣ tan (x) + sec (x) ∣

= [ln ∣ tan (x) + sec (x) ∣]_{0}^{\frac{π}{2}}

Compute the boundaries:

diverges

= diverges

t \to 0 lim (\frac{tan ( 10 t )}{sin ( 2 t )})

\frac{d}{d x} (x \cdot e^{3 x})

\int \frac{1}{6 - x} d x

6 π x^{2}

\int 14 x^{- 1} d x

What is the integral from 0 to pi/2 of sec(x) ?
The integral from 0 to pi/2 of sec(x) is diverges