What is (\partial)/(\partial x)(3x^2+2xy-y^2) ?

The answer to (\partial)/(\partial x)(3x^2+2xy-y^2) is 6x+2y

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(\partial)/(\partial x)(3x^2+2xy-y^2)

\frac{\partial}{\partial x} (3 x^{2} + 2 x y - y^{2})

6 x + 2 y

Solution steps

\frac{\partial}{\partial x} (3 x^{2} + 2 x y - y^{2})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (3 x^{2}) + \frac{\partial}{\partial x} (2 x y) - \frac{\partial}{\partial x} (y^{2})

\frac{\partial}{\partial x} (3 x^{2}) = 6 x

\frac{\partial}{\partial x} (2 x y) = 2 y

\frac{\partial}{\partial x} (y^{2}) = 0

= 6 x + 2 y - 0

Simplify

= 6 x + 2 y

x y^{^{'}} + 2 y = 3 e^{x}

- \frac{3}{5000} r^{3} + \frac{9}{50} r^{2}

\frac{( x ^{2} - x - 2 )}{( x ^{2} - 6 x + 9 )}

x \to 9 + lim (x^{2} + 5 x + 7)

f (x) = x^{3}, (- 1, - 1)

What is (\partial)/(\partial x)(3x^2+2xy-y^2) ?
The answer to (\partial)/(\partial x)(3x^2+2xy-y^2) is 6x+2y