What is laplacetransform sin(t) ?

The answer to laplacetransform sin(t) is 1/(s^2+1)

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laplacetransform sin(t)

laplace transform

sin (t)

\frac{1}{s ^{2} + 1}

Solution steps

L {sin (t)}

Use Laplace Transform table:

L {sin (a t)} = \frac{a}{s ^{2} + a ^{2}}

L {sin (t)} = \frac{1}{s ^{2} + 1 ^{2}}

= \frac{1}{s ^{2} + 1 ^{2}}

= \frac{1}{s ^{2} + 1}

x \to 0 + lim (e^{x})

\frac{d ^{2}}{d x ^{2}} ((4 x^{2} + 2 x) sin (x))

(- 2, 2), (2, - 1)

\frac{d}{d x} (3 x^{4} - 16 x^{3} + 18 x^{2})

\int_{0}^{\frac{π}{24}} tan (12 x) d x

What is laplacetransform sin(t) ?
The answer to laplacetransform sin(t) is 1/(s^2+1)