What is (\partial)/(\partial x)(x^2+xy-10) ?

The answer to (\partial)/(\partial x)(x^2+xy-10) is 2x+y

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(\partial)/(\partial x)(x^2+xy-10)

\frac{\partial}{\partial x} (x^{2} + x y - 10)

2 x + y

Solution steps

\frac{\partial}{\partial x} (x^{2} + x y - 10)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x^{2}) + \frac{\partial}{\partial x} (x y) - \frac{\partial}{\partial x} (10)

\frac{\partial}{\partial x} (x^{2}) = 2 x

\frac{\partial}{\partial x} (x y) = y

\frac{\partial}{\partial x} (10) = 0

= 2 x + y - 0

Simplify

= 2 x + y

\frac{d}{d x} (2 x^{3} cos (x) sin (x))

n = 0 \sum \infty \frac{( - 1 ) ^{n}}{2}

t \to 0 lim (\frac{e ^{7 t} - 1}{sin ( t )})

\frac{\partial}{\partial x} (3 x + 7)

x^{3 π}

What is (\partial)/(\partial x)(x^2+xy-10) ?
The answer to (\partial)/(\partial x)(x^2+xy-10) is 2x+y