What is the derivative of sqrt(7x+8) ?

The derivative of sqrt(7x+8) is 7/(2sqrt(7x+8))

What is the first derivative of sqrt(7x+8) ?

The first derivative of sqrt(7x+8) is 7/(2sqrt(7x+8))

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derivative of

7 x + 8

\frac{7}{2 7 x + 8}

Solution steps

\frac{d}{d x} (7 x + 8)

Apply the chain rule:

\frac{1}{2 7 x + 8} \frac{d}{d x} (7 x + 8)

= \frac{1}{2 7 x + 8} \frac{d}{d x} (7 x + 8)

\frac{d}{d x} (7 x + 8) = 7

= \frac{1}{2 7 x + 8} \cdot 7

Simplify

\frac{1}{2 7 x + 8} \cdot 7 : \frac{7}{2 7 x + 8}

= \frac{7}{2 7 x + 8}

\int \frac{3}{( 3 x + 4 ) ln ( 3 x + 4 )} d x

x \to 0 lim (sin (3 x) cot (x))

x \to - 7 + lim (\frac{- x ^{2}}{x + 7})

x \to 1 lim (\frac{- 2 x ^{2}}{x - 1})

\int_{0}^{1} 2 ln (x) d x

What is the derivative of sqrt(7x+8) ?
The derivative of sqrt(7x+8) is 7/(2sqrt(7x+8))
What is the first derivative of sqrt(7x+8) ?
The first derivative of sqrt(7x+8) is 7/(2sqrt(7x+8))