What is the integral of (arcsin(x))/(sqrt(1-x^2)) ?

The integral of (arcsin(x))/(sqrt(1-x^2)) is (arcsin^2(x))/2+C

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integral of (arcsin(x))/(sqrt(1-x^2))

\int \frac{arcsin ( x )}{1 - x ^{2}} d x

\frac{arcsin ^{2} ( x )}{2} + C

Solution steps

\int \frac{arcsin ( x )}{1 - x ^{2}} d x

Apply u-substitution

: \int u d u

= \int u d u

Apply the Power Rule

: \frac{u ^{2}}{2}

= \frac{u ^{2}}{2}

Substitute back

u = arcsin (x)

= \frac{arcsin ^{2} ( x )}{2}

Add a constant to the solution

= \frac{arcsin ^{2} ( x )}{2} + C

\frac{\partial}{\partial x} (\frac{( 3 x ^{4} - 2 x y )}{y ^{2}})

\int \frac{2 x}{x ^{4} + 4} d x

\frac{d y}{d x} = \frac{6 x}{y}

x^{2} + 1

\int \frac{3 x}{x ^{2} + 6 x + 9} d x

What is the integral of (arcsin(x))/(sqrt(1-x^2)) ?
The integral of (arcsin(x))/(sqrt(1-x^2)) is (arcsin^2(x))/2+C