What is (\partial)/(\partial x)(cos(x^2*y)) ?

The answer to (\partial)/(\partial x)(cos(x^2*y)) is -sin(x^2y)*2yx

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(\partial)/(\partial x)(cos(x^2*y))

\frac{\partial}{\partial x} (cos (x^{2} \cdot y))

- sin (x^{2} y) \cdot 2 y x

Solution steps

\frac{\partial}{\partial x} (cos (x^{2} y))

Treat

y

as a constant

Apply the chain rule:

- sin (x^{2} y) \frac{\partial}{\partial x} (x^{2} y)

= - sin (x^{2} y) \frac{\partial}{\partial x} (x^{2} y)

\frac{\partial}{\partial x} (x^{2} y) = 2 y x

= - sin (x^{2} y) \cdot 2 y x

h \to 0 lim (\frac{4 ^{h} - 1}{h})

x \to \frac{13 π}{3} lim (cos (x))

\int \frac{e ^{x}}{x} d x

x^{3}, x^{2} + x, - 1, 1.6

\frac{8 x + 1}{x}

What is (\partial)/(\partial x)(cos(x^2*y)) ?
The answer to (\partial)/(\partial x)(cos(x^2*y)) is -sin(x^2y)*2yx