What is the tangent of f(x)=x^2-2x+1,\at x=-1 ?

The tangent of f(x)=x^2-2x+1,\at x=-1 is y=-4x

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tangent of f(x)=x^2-2x+1,\at x=-1

tangent of

f (x) = x^{2} - 2 x + 1, at x = - 1

y = - 4 x

Solution steps

Find the tangent point:

(- 1, 4)

Find the slope of

f (x) = x^{2} - 2 x + 1 : \frac{df ( x )}{d x} = 2 x - 2

Compute the slope of

f (x) = x^{2} - 2 x + 1

x = - 1 : m = - 4

Find the line with slope m=

- 4

and passing through

(- 1, 4) : y = - 4 x

y = - 4 x

f (x) = 3 + 2 x - x^{2}, g (x) = x^{2} - 4 x + 3

y = x, y = \frac{1}{4} x, x = 25

f (x) = - x^{3}

\frac{\partial}{\partial y} (\frac{1}{2} sin (2 x - y))

\int_{5}^{\infty} x e^{- 2 x} d x

What is the tangent of f(x)=x^2-2x+1,\at x=-1 ?
The tangent of f(x)=x^2-2x+1,\at x=-1 is y=-4x