What is the tangent of f(x)=7x^2+4x ?

The tangent of f(x)=7x^2+4x is y=(14a_{0}+4)x-7a_{0}^2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of f(x)=7x^2+4x

tangent of

f (x) = 7 x^{2} + 4 x

y = (14 a_{0} + 4) x - 7 a_{0}^{2}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, 7 a_{0}^{2} + 4 a_{0})

Find the slope of

f (x) = 7 x^{2} + 4 x : \frac{df ( x )}{d x} = 14 x + 4

Compute the slope of

f (x) = 7 x^{2} + 4 x

x = a_{0} : m = 14 a_{0} + 4

Find the line with slope m=

14 a_{0} + 4

and passing through

(a_{0}, 7 a_{0}^{2} + 4 a_{0}) : y = (14 a_{0} + 4) x - 7 a_{0}^{2}

y = (14 a_{0} + 4) x - 7 a_{0}^{2}

\int 3 e^{x} + 8 x^{3} + 4 x d x

\frac{d}{d x} (cos (\frac{1}{4} x^{3}))

\frac{d}{d x} (\frac{e ^{4 x}}{x ^{8}})

\int cos^{2} (t) sin (t) d t

n = 3 \sum \infty (\frac{4}{5})^{n}

What is the tangent of f(x)=7x^2+4x ?
The tangent of f(x)=7x^2+4x is y=(14a_{0}+4)x-7a_{0}^2