What is the solution for (dy)/(dx)=e^{2y+9x} ?

The solution for (dy)/(dx)=e^{2y+9x} is y=-(ln(-2/9 e^{9x}-c_{1}))/2

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(dy)/(dx)=e^{2y+9x}

\frac{d y}{d x} = e^{2 y + 9 x}

y = - \frac{ln ( - \frac{2}{9} e ^{9 x} - c _{1} )}{2}

Solution steps

\frac{d y}{d x} = e^{2 y + 9 x}

Solve separable ODE:

y = - \frac{ln ( - \frac{2}{9} e ^{9 x} - c _{1} )}{2}

y = - \frac{ln ( - \frac{2}{9} e ^{9 x} - c _{1} )}{2}

\frac{d x}{d t} = k x

\frac{d}{d x} ((x^{3} + 4 x)^{7})

x \to 0 lim (3 x^{x})

\int \frac{( x - 1 )}{x} d x

\int (x^{2} - x + 2) d x

What is the solution for (dy)/(dx)=e^{2y+9x} ?
The solution for (dy)/(dx)=e^{2y+9x} is y=-(ln(-2/9 e^{9x}-c_{1}))/2