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Popular >

(dy)/(dt)= 1/5 t

Solution

\frac{d y}{d t} = \frac{1}{5} t

Solution

y = \frac{t ^{2}}{10} + c_{1}

Solution steps

\frac{d y}{d t} = \frac{1}{5} t

Substitute

\frac{d y}{d t}

with

y^{'} (t)

y^{^{'}} (t) = \frac{1}{5} t

If

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int \frac{1}{5} t d t

\int \frac{1}{5} t d t = \frac{t ^{2}}{10} + c_{1}

y = \frac{t ^{2}}{10} + c_{1}

Popular Examples

y^{''}-0.2y^'+0.01y=0,y(0)=12,y^'(0)=b

y^{^{''}} - 0.2 y^{^{'}} + 0.01 y = 0, y (0) = 12, y^{^{'}} (0) = b

derivative of ((x^2/8+x-1/x)^4)

\frac{d}{d x} ((\frac{x ^{2}}{8} + x - \frac{1}{x})^{4})

derivative of 9/(t^2)-3/t derivative of

\frac{9}{t ^{2}} - \frac{3}{t}

integral of sin^5(5x)cos^3(5x)

\int sin^{5} (5 x) cos^{3} (5 x) d x

(\partial)/(\partial x)((-6x-y)/(y^2+2x^2))

\frac{\partial}{\partial x} (\frac{- 6 x - y}{y ^{2} + 2 x ^{2}})

Frequently Asked Questions (FAQ)

What is the solution for (dy)/(dt)= 1/5 t ?
The solution for (dy)/(dt)= 1/5 t is y=(t^2)/(10)+c_{1}