What is the derivative of-(4x/((-x+1)^2(x+1)^2)) ?

The derivative of-(4x/((-x+1)^2(x+1)^2)) is (4(3x^2+1))/((x+1)^3(x-1)^3)

What is the first derivative of-(4x/((-x+1)^2(x+1)^2)) ?

The first derivative of-(4x/((-x+1)^2(x+1)^2)) is (4(3x^2+1))/((x+1)^3(x-1)^3)

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\frac{d}{d x} (- \frac{4 x}{( - x + 1 ) ^{2} ( x + 1 ) ^{2}})

\frac{4 ( 3 x ^{2} + 1 )}{( x + 1 ) ^{3} ( x - 1 ) ^{3}}

Solution steps

\frac{d}{d x} (- \frac{4 x}{( - x + 1 ) ^{2} ( x + 1 ) ^{2}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 4 \frac{d}{d x} (\frac{x}{( - x + 1 ) ^{2} ( x + 1 ) ^{2}})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= - 4 \cdot \frac{\frac{d x}{d x} ( - x + 1 ) ^{2} ( x + 1 ) ^{2} - \frac{d}{d x} ( ( - x + 1 ) ^{2} ( x + 1 ) ^{2} ) x}{( ( - x + 1 ) ^{2} ( x + 1 ) ^{2} ) ^{2}}

\frac{d x}{d x} = 1

\frac{d}{d x} ((- x + 1)^{2} (x + 1)^{2}) = 4 x^{3} - 4 x

= - 4 \cdot \frac{1 \cdot ( - x + 1 ) ^{2} ( x + 1 ) ^{2} - ( 4 x ^{3} - 4 x ) x}{( ( - x + 1 ) ^{2} ( x + 1 ) ^{2} ) ^{2}}

Simplify

- 4 \cdot \frac{1 \cdot ( - x + 1 ) ^{2} ( x + 1 ) ^{2} - ( 4 x ^{3} - 4 x ) x}{( ( - x + 1 ) ^{2} ( x + 1 ) ^{2} ) ^{2}} : \frac{4 ( 3 x ^{2} + 1 )}{( x + 1 ) ^{3} ( x - 1 ) ^{3}}

= \frac{4 ( 3 x ^{2} + 1 )}{( x + 1 ) ^{3} ( x - 1 ) ^{3}}

\frac{( 2 s + 3 )}{s ^{2} + 6 s + 13}

\frac{1}{e ( s - 1 ) ^{3}}

sin (π x)

y = 3 + 5 x^{2} - 2 x^{3}

x \to 0 lim ((5 x + 2)^{3})

What is the derivative of-(4x/((-x+1)^2(x+1)^2)) ?
The derivative of-(4x/((-x+1)^2(x+1)^2)) is (4(3x^2+1))/((x+1)^3(x-1)^3)
What is the first derivative of-(4x/((-x+1)^2(x+1)^2)) ?
The first derivative of-(4x/((-x+1)^2(x+1)^2)) is (4(3x^2+1))/((x+1)^3(x-1)^3)