What is the derivative of ln(2x-1) ?

The derivative of ln(2x-1) is 2/(2x-1)

What is the first derivative of ln(2x-1) ?

The first derivative of ln(2x-1) is 2/(2x-1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

ln (2 x - 1)

\frac{2}{2 x - 1}

Solution steps

\frac{d}{d x} (ln (2 x - 1))

Apply the chain rule:

\frac{1}{2 x - 1} \frac{d}{d x} (2 x - 1)

= \frac{1}{2 x - 1} \frac{d}{d x} (2 x - 1)

\frac{d}{d x} (2 x - 1) = 2

= \frac{1}{2 x - 1} \cdot 2

Simplify

\frac{1}{2 x - 1} \cdot 2 : \frac{2}{2 x - 1}

= \frac{2}{2 x - 1}

\int - x^{7} e^{x^{8} - 7} - 2 x d x

\frac{d}{d x} (\frac{cos ( x )}{2 sin ^{2} ( x )})

\frac{d}{d x} (e^{\frac{1}{x}})

\frac{d}{d x} (x^{- 2} (4 + 3 x^{- 3}))

\int (e^{x} - x^{e} + \frac{5}{x}) d x

What is the derivative of ln(2x-1) ?
The derivative of ln(2x-1) is 2/(2x-1)
What is the first derivative of ln(2x-1) ?
The first derivative of ln(2x-1) is 2/(2x-1)