What is the first d/(dn)(5^n) ?

The first d/(dn)(5^n) is 5^nln(5)

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d/(dn)(5^n)

\frac{d}{d n} (5^{n})

5^{n} ln (5)

Solution steps

\frac{d}{d n} (5^{n})

Apply the derivative exponent rule:

\frac{d}{d x} (a^{x}) = a^{x} ln (a)

= 5^{n} ln (5)

x \to 4 lim (\frac{8}{x})

\int \frac{1}{x ^{2} + 2 x + 5} d x

y = 6 + 4 x^{2} - 2 x^{3}

\int_{1}^{\infty} 2 e^{- x} d x

\frac{d}{d x} ((3 x)^{2 x})