What is (\partial)/(\partial y)(yze^x) ?

The answer to (\partial)/(\partial y)(yze^x) is e^xz

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(\partial)/(\partial y)(yze^x)

\frac{\partial}{\partial y} (yz e^{x})

e^{x} z

Solution steps

\frac{\partial}{\partial y} (yz e^{x})

Treat

z, x

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= z e^{x} \frac{\partial}{\partial y} (y)

Apply the common derivative:

\frac{\partial}{\partial y} (y) = 1

= z e^{x} \cdot 1

Simplify

= e^{x} z

\int ln (1 + x^{2}) d x

\frac{\partial}{\partial x} ((2 x + 8) ln (x y))

\int sin (20 x) cos (11 x) d x

f^{^{'}} (x) = 3 x + 2

x \to 3 lim (\frac{1}{( x - 3 ) ^{3}})

What is (\partial)/(\partial y)(yze^x) ?
The answer to (\partial)/(\partial y)(yze^x) is e^xz