What is the tangent of x^2+2xy-y^2+x=51,(5,7) ?

The tangent of x^2+2xy-y^2+x=51,(5,7) is y= 25/4 x-97/4

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tangent of x^2+2xy-y^2+x=51,(5,7)

tangent of

x^{2} + 2 x y - y^{2} + x = 51, (5, 7)

y = \frac{25}{4} x - \frac{97}{4}

Solution steps

Find the slope of

x^{2} + 2 x y - y^{2} + x = 51 : \frac{d y}{d x} = \frac{- 2 x - 1 - 2 y}{2 ( x - y )}

Compute the slope of

x^{2} + 2 x y - y^{2} + x = 51

(5, 7) : m = \frac{25}{4}

Find the line with slope m=

\frac{25}{4}

and passing through

(5, 7) : y = \frac{25}{4} x - \frac{97}{4}

y = \frac{25}{4} x - \frac{97}{4}

(4.3) (4.6)

\int e^{- x} + e^{- 3 x} d x

n = 0 \sum \infty \frac{n !}{n ^{n}}

\int (\frac{1}{x ^{9}} - x^{9} - \frac{1}{8}) d x

\frac{x - 5}{x - 25}

What is the tangent of x^2+2xy-y^2+x=51,(5,7) ?
The tangent of x^2+2xy-y^2+x=51,(5,7) is y= 25/4 x-97/4